Lens Formula and Magnification A convex lens...
Open in App
Solution Here, u=−15 cm m=vu=−3 (Since the image is inverted) ⇒v=−3u=45 cm Now using the lens formula, 1v−1u=1f ⇒145−1−15=1f ⇒f=454=11.25 cm
Similar questions
Join BYJU'S Learning Program
Related Videos
Lens Formula, Magnification and Power of Lens
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program
As an enthusiast and expert in the field of physics, particularly optics and lens formulas, I can confidently speak to the concepts mentioned in the article. My knowledge is grounded in both theoretical principles and practical applications, allowing me to provide a thorough understanding of the topic.
Let's delve into the content of the article:
-
Lens Formula and Magnification: The lens formula, ( \frac{1}{v} - \frac{1}{u} = \frac{1}{f} ), is a fundamental equation in optics. Here, ( u ) represents the object distance, ( v ) is the image distance, and ( f ) is the focal length of the lens. The formula establishes a relationship between these parameters for a lens.
In the given example, the object distance ( u ) is -15 cm (negative since the object is on the same side as the incident light), and the image distance ( v ) is -45 cm (negative because the image is inverted). Solving the lens formula equation yields the focal length ( f ) as 11.25 cm.
-
Convex Lens: The article refers to a convex lens. Convex lenses are thicker in the center than at the edges and converge parallel rays of light. They are capable of forming both real and virtual images depending on the object's position relative to the lens.
-
Magnification: The magnification (( m )) is given by the formula ( m = \frac{v}{u} ). In the provided example, the magnification is -3, indicating that the image is inverted and three times the size of the object.
-
Ray Diagram: The article does not explicitly mention a ray diagram, but it is a crucial aspect of understanding image formation by lenses. A ray diagram involves drawing incident rays from the object and determining the path of these rays through the lens to locate the image.
The article touches upon common questions related to convex lenses, focal lengths, object distances, magnification, and image characteristics. If you have further questions or need clarification on any of these concepts, feel free to ask.
