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$$BeO $$ is almost insoluble in water due to high lattice energy. $$ BeSO_4 $$ is soluble in water due to high hydration energy of $$Be^{2+} $$ ion. The high hydration energy of $$Be^{2+} $$ in $$BeSO_4 $$ overcomes the lattice energy factors and therefore $$BeSO_4 $$ is soluble in water.
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Explain the following:
$$BeO $$ is almost insoluble but $$ BeSO_4 $$ is soluble in water.
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BeO is almost insoluble but BeSO4 is soluble in water. Explain.
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BeO is almost insoluble but BeSO4 is soluble in water?
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How would you explain the following observations? (i) BeO is almost insoluble but BeSO4 in soluble in water, (ii) BaO is soluble but BaSO4 is insoluble in water, (iii) LiI is more soluble than KI in ethanol.
