What is the order Na+ Mg2+ O2 and F from smallest to largest radius?
Hence, the Correct Order Of
Answer and Explanation: The order of ionic radii from smallest to largest is as follows: Al3+<Mg2+<Na+<K+ A l 3 + < M g 2 + < N a + < K + .
Answer and Explanation: The correct option is d. O2− has the largest radius as it has a minimum z-effect. The negatively charged anions are greater than cations and neutrally charged molecules.
Updated On: 27-06-2022. O2− is bigger ion among the given four. Among isoelectronic ions, the more the negative charge on the ion, the more is its size. The order is O2−>F−>Na+>Mg2+.
The largest and smallest ion in O²-, F-, Na+, and Mg2+ is O²- and Mg2+ Respectively.
Hence,in case of Mg^2+ electrostatic force between the nucleus and protons is stronger than F-. Therefore,Mg^2+ ion is smaller than F- ion.
But they have different number of protons. F− has 9 protons, Ne has 10 protons and Na+ has 11 protons. Since F− has lowest number of nuclear charge, it will have largest size.
Therefore, even though a sodium ion and an oxygen ion have the same number of electron shells and the same number of electrons, a sodium ion is smaller because it has a greater number of protons. Or in other words, an oxygen ion is larger because it has fewer protons.
Rank from largest to smallest radius. To rank items as equivalent, overlap them. First locate each of the elements on the periodic table. Then, keeping in mind that ionic radii increase for ions with the same charge going down a row, sort the ions in order of increasing radii.
Helium has the smallest atomic radius.
Which is the smallest size Na+ or Mg2+?
Mg2+ is smaller than Na+ because Mg2+ has an extra electron.
(i) The sodium ion (Na+) is larger than the magnesium ion (Mg2+) due to two effects.

Thus, the correct order of increasing ionic radii is Mg2+ < Na+ <F−< O2−
Hence, the Correct Order Of Ionic Radii For Na + , Mg 2 + , F − and O 2 − is Mg 2 + < Na + < F - < O 2 - .
The correct option is: a Al3+ Explanation:These are isoelectronic ions ions with same number of electrons and for isoelectronic ions greater the positive nuclear charge greater is the force of attraction on the electrons by the nucleus and the smaller is the size of the ion. Thus Al3+ has the smallest size.
(8 points) Why is the Mg2+ ion smaller than F–, even though they are isoelectronic? Because while having the same number of electrons, Mg2+ has 12 protons and F– has only 9. Therefore, the electron attraction to the nucleus is greater in Mg2+ making it smaller.
The fact the fluoride anion is negative and magnesium cation is positive means you've already applied electronegativity to the system in order to ionize them. So because it has more particles in pulling in the e- than Mg+ will have a smaller radius!
Mg2+ ion is smaller than O2- ion though both are iso-electronic. The nuclear charge in Mg2+ is + 12 and O2- is + 8 so with the increase in nuclear charge the size decreases and hence O2- > Mg2+.
Therefore, the arrangement of the given species in order of their increasing ionic radii is as follows: Al3+ < Mg2+ < Na+ < F– < O2– < N3–
Hence, the Correct Order Of Ionic Radii For Na + , Mg 2 + , F − and O 2 − is Mg 2 + < Na + < F - < O 2 - .
Do F and Na+ have the same radius?
For elements with the same number of electrons, the atom with more protons in the nucleus or the higher effective nuclear charge has the smaller atomic radius. In the case of Na+ and F-, Na+ has the smaller ionic radius because it has a stronger pull from the nucleus, causing electrons to be pulled tighter in.
Among the iso - electronic ions Na^ + , Mg^2 + and Al^3 + , Na^ + ion has the largest size.
Atomic radii vary in a predictable way across the periodic table. As can be seen in the figures below, the atomic radius increases from top to bottom in a group, and decreases from left to right across a period. Thus, helium is the smallest element, and francium is the largest.
Ionic radius increases down the group ,in the following option strontium is having the largest ionic radius as the elements arranged in periodic table is Berilyium, Magnesium, Calcium and Strontium. These elements belongs to alkali earth metals.
Na+ is the smallest as it has lost an electron from its outermost shell thereby pulled a bit more towards the nucleus. F^- has the largest size. As the atomic no. Increases nuclear charge increases.
More the nuclear charge on ion, electrons are more strongly attracted and thus size decreases. Hence, among the given ions Al3+ is the smallest ion.
Atomic Size
The smallest atom on the periodic table is helium, He, and has a radius of 31 pm.
Therefore, the ion with the greatest atomic number has the smallest atomic radius and the ion with the smallest atomic number has the largest radius.
Therefore, Ca2+ has the smallest ionic radius.
(b) The increasing order of ionic radii is Al3+<Mg2+<Na+<F−<O2−<N3−.
Which of the following is smallest in size in Na+ F O2?
Here Na+ is having most protons so it will be having highest nuclear charge, thus smallest size.
Al3+ is the smallest because it has highest number of protons (13) among Na⊕,Mg2+ and Al3+ ions, due to which effective nuclear charge is more.
O and O2− have an equal atomic number which is 8. However, the two species have different numbers of electrons, O has 8 while O2− has 10. This means that the latter has larger orbitals and less tightly held outer electrons. Therefore, O2− has a larger atomic radius.
F has a smaller radius than F− because an additional electron causes greater repulsion in F− .
The ions O2–, F–, Na+, Mg2+ and Al3+ are isoelectronic.
These electrons go in the outermost shells. Also, when an atom loses electrons, it clings ever more tightly to the ones it has left, further reducing the ionic radius. therefore the order of ionic radii will be: Al3+<Mg2+<Na+<F−<O2−<N3− (increasing order)
It is fairly easy to arrange the atoms according to atomic size. We know that atomic size increases from right to left and from top to bottom in the Periodic Table. The smallest atoms are at the top right and the largest atoms are at the lower left of the Periodic Table.
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Ionic Radii and Isoelectronic Series.
As O2− and F− are isoelectronic, therefore, size of O2−>F− Q.
Explanation: The ionic radii of alkali metal ions are larger than those of alkaline earth metal ions belonging to the same period. Also, the ionic radii increases down the group and decreases as we move across a period. Hence, the correct order of the ionic radii is Na+>Li+>Mg2+>Be2+
Which of the following will be smallest in size?
A cation is smaller is size because the lesser electrons will be more tightly held by the nucleus therefore reducing the atomic size.
As the nuclear charge per electron is maximum in F−, it is the smallest in size.
An atom after losing an electron forms a cation and since the net charge on the atom increases the atomic size increases. The greater the charge on the atom smaller the size of the ion so Al(III) cation is smallest in size.
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Ionic Radii and Isoelectronic Series.
Hence, the increasing order of ionic radii is Na+ > Mg2+ > Al3+ > Si4+.
Helium has the smallest atomic radius.
The increasing order of the ionic radius is Mn+7<V+5<Ca+2<K+Cl−<S2<P3−. As the effective nuclear charge increases, the attraction of the nucleus for the valence electrons increases and hence the ionic radii decreases.
Explanation: The ionic radii of alkali metal ions are larger than those of alkaline earth metal ions belonging to the same period. Also, the ionic radii increases down the group and decreases as we move across a period. Hence, the correct order of the ionic radii is Na+>Li+>Mg2+>Be2+
The ionic radii of cations follow the same trends as atomic radii. They increase from top to bottom and from right to left in the Periodic Table. Thus, the ion with the largest radius is closest to the lower left corner of the Periodic Table, and that is the K+ ion.
The ionic radii of F− and O2− respectively are 1.33 ∘A and 1.4 ∘A while the covalent radius of N is 0.74 ∘A.
Which has the smallest ionic radius Na+?
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Ionic Radii and Isoelectronic Series.
Ionic radius increases down the group ,in the following option strontium is having the largest ionic radius as the elements arranged in periodic table is Berilyium, Magnesium, Calcium and Strontium.
Arranging the atoms
We know that atomic size increases from right to left and from top to bottom in the Periodic Table. The smallest atoms are at the top right and the largest atoms are at the lower left of the Periodic Table.
Among isoelectronic ions, ionic radius decreases as the positive charge increases. Therefore, the ionic radii decrease in the order: He+>Li2+>Be3+